(1/3)^(2x)=729

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Solution for (1/3)^(2x)=729 equation: 



(1/3)^(2x)=729

We move all terms to the left:

(1/3)^(2x)-(729)=0



Domain of the equation: 3)^2x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/3)^2x-729=0

We multiply all the terms by the denominator


(+1-729*3)^2x=0

We add all the numbers together, and all the variables

(-2186)^2x=0

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